64x^2-24x=0

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Solution for 64x^2-24x=0 equation:



64x^2-24x=0
a = 64; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·64·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*64}=\frac{0}{128} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*64}=\frac{48}{128} =3/8 $

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